Description
The incredible pressures at this depth are starting to put a strain on your submarine. The submarine has polymerization equipment that would produce suitable materials to reinforce the submarine, and the nearby volcanically-active caves should even have the necessary input elements in sufficient quantities.
The submarine manual contains instructions for finding the optimal polymer formula; specifically, it offers a polymer template and a list of pair insertion rules (your puzzle input). You just need to work out what polymer would result after repeating the pair insertion process a few times.
For example:
NNCB
CH -> B
HH -> N
CB -> H
NH -> C
HB -> C
HC -> B
HN -> C
NN -> C
BH -> H
NC -> B
NB -> B
BN -> B
BB -> N
BC -> B
CC -> N
CN -> C
The first line is the polymer template - this is the starting point of the process.
The following section defines the pair insertion rules. A rule like AB -> C
means that when elements A
and B
are immediately adjacent, element C
should be inserted between them. These insertions all happen simultaneously.
So, starting with the polymer template NNCB
, the first step simultaneously considers all three pairs:
- The first pair (
NN
) matches the ruleNN -> C
, so element*C*
is inserted between the firstN
and the secondN
. - The second pair (
NC
) matches the ruleNC -> B
, so element*B*
is inserted between theN
and theC
. - The third pair (
CB
) matches the ruleCB -> H
, so element*H*
is inserted between theC
and theB
.
Note that these pairs overlap: the second element of one pair is the first element of the next pair. Also, because all pairs are considered simultaneously, inserted elements are not considered to be part of a pair until the next step.
After the first step of this process, the polymer becomes N*C*N*B*C*H*B
.
Here are the results of a few steps using the above rules:
Template: NNCB
After step 1: NCNBCHB
After step 2: NBCCNBBBCBHCB
After step 3: NBBBCNCCNBBNBNBBCHBHHBCHB
After step 4: NBBNBNBBCCNBCNCCNBBNBBNBBBNBBNBBCBHCBHHNHCBBCBHCB
This polymer grows quickly. After step 5, it has length 97; After step 10, it has length 3073. After step 10, B
occurs 1749 times, C
occurs 298 times, H
occurs 161 times, and N
occurs 865 times; taking the quantity of the most common element (B
, 1749) and subtracting the quantity of the least common element (H
, 161) produces 1749 - 161 = *1588*
.
Apply 10 steps of pair insertion to the polymer template and find the most and least common elements in the result. What do you get if you take the quantity of the most common element and subtract the quantity of the least common element?
--- Part Two ---
The resulting polymer isn't nearly strong enough to reinforce the submarine. You'll need to run more steps of the pair insertion process; a total of 40 steps should do it.
In the above example, the most common element is B
(occurring 2192039569602
times) and the least common element is H
(occurring 3849876073
times); subtracting these produces *2188189693529*
.
Apply 40 steps of pair insertion to the polymer template and find the most and least common elements in the result. What do you get if you take the quantity of the most common element and subtract the quantity of the least common element?
Notes
- 14-1: Another fairly simple data processing problem, and I got the first part done in a couple hours.
- 14-2: Aaaaand we've come to another optimization issue where 14-1's algorithm is too inefficient to handle real data at scale. Oof.